Hoe kan ik zorgen dat hij alles weergeeft

ik heb dit:

$query = mysql_query("SELECT * FROM aanmeldingen WHERE lidid = ". $_GET[lidid] ."");
$result = mysql_num_rows($query);

if($result == 1){

Hij geeft nu maar 1 ding weer maar ik moet alles hebben wat daar is.

Probeer is zonder die result

[COLOR= #0000BB]<?php
$query[/COLOR] [COLOR= #007700]=[/COLOR] [URL="http://www.php.net/mysql_query"]mysql_query[/URL][COLOR= #007700]([/COLOR][COLOR= #DD0000]"SELECT * FROM aanmeldingen WHERE lidid = "[/COLOR][COLOR= #007700].[/COLOR] [COLOR= #0000BB]$_GET[/COLOR][COLOR= #007700][[/COLOR][COLOR= #DD0000]lidid[/COLOR][COLOR= #007700]] .[/COLOR][COLOR= #DD0000]""[/COLOR][COLOR= #007700]);[/COLOR]
[URL="http://www.php.net/while"]while[/URL] [COLOR= #007700]([/COLOR][COLOR= #0000BB]$result[/COLOR] [COLOR= #007700]=[/COLOR] [URL="http://www.php.net/mysql_fetch_assoc"]mysql_fetch_assoc[/URL][COLOR= #007700]([/COLOR][COLOR= #0000BB]$query[/COLOR][COLOR= #007700]))
{[/COLOR]
[COLOR= #FF8000]//Welke info wil je?[/COLOR]
[COLOR= #007700]}[/COLOR]
?>